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x-3x^2=-6
We move all terms to the left:
x-3x^2-(-6)=0
We add all the numbers together, and all the variables
-3x^2+x+6=0
a = -3; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-3)·6
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{73}}{2*-3}=\frac{-1-\sqrt{73}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{73}}{2*-3}=\frac{-1+\sqrt{73}}{-6} $
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