x-4(2x-8)x=-6

Solution for x-4(2x-8)x=-6 equation:

x-4(2x-8)x=-6

We move all terms to the left:

x-4(2x-8)x-(-6)=0

We add all the numbers together, and all the variables

x-4(2x-8)x+6=0

We multiply parentheses

-8x^2+x+32x+6=0

We add all the numbers together, and all the variables

-8x^2+33x+6=0

a = -8; b = 33; c = +6;
Δ = b2-4ac
Δ = 332-4·(-8)·6
Δ = 1281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1281}}{2*-8}=\frac{-33-\sqrt{1281}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1281}}{2*-8}=\frac{-33+\sqrt{1281}}{-16}
$