x-4(3+2x)=3(3x-4)*

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Solution for x-4(3+2x)=3(3x-4)* equation: 



x-4(3+2x)=3(3x-4)*

We move all terms to the left:

x-4(3+2x)-(3(3x-4)*)=0

We add all the numbers together, and all the variables

x-4(2x+3)-(3(3x-4)*)=0

We multiply parentheses

x-8x-(3(3x-4)*)-12=0



We calculate terms in parentheses: -(3(3x-4)*), so:

3(3x-4)*

We multiply parentheses

9x-12

Back to the equation:

-(9x-12)



We add all the numbers together, and all the variables

-7x-(9x-12)-12=0

We get rid of parentheses

-7x-9x+12-12=0

We add all the numbers together, and all the variables

-16x=0

x=0/-16

x=0

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