x-4(3-2x)=3(x-4)

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Solution for x-4(3-2x)=3(x-4) equation: 



x-4(3-2x)=3(x-4)

We move all terms to the left:

x-4(3-2x)-(3(x-4))=0

We add all the numbers together, and all the variables

x-4(-2x+3)-(3(x-4))=0

We multiply parentheses

x+8x-(3(x-4))-12=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

9x-(3x-12)-12=0

We get rid of parentheses

9x-3x+12-12=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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