x-4(x+3)=1/3(3x+3)-6

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Solution for x-4(x+3)=1/3(3x+3)-6 equation: 



x-4(x+3)=1/3(3x+3)-6

We move all terms to the left:

x-4(x+3)-(1/3(3x+3)-6)=0



Domain of the equation: 3(3x+3)-6)!=0

x∈R



We multiply parentheses

x-4x-(1/3(3x+3)-6)-12=0

We multiply all the terms by the denominator


x*3(3x+3)-6)-4x*3(3x+3)-6)-(1-12*3(3x+3)-6)=0

We add all the numbers together, and all the variables

x*3(3x+3)-6)-4x*3(3x+3)-6)-(1-12*3(3x=0

Wy multiply elements

3x^2(3-6)-4x*3(3x+3)-12*3(3x-6)-(1=0

We add all the numbers together, and all the variables

3x^2(-3)-4x*3(3x+3)-12*3(3x-6)-(1=0

We add all the numbers together, and all the variables

3x^2(-3)-4x*3(3x+3)-12*3(3x-6)=0

Wy multiply elements

3x^2(-3)-12x^2(3-36x(3=0

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