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x-4(x+3)=1/3(3x+3-6
We move all terms to the left:
x-4(x+3)-(1/3(3x+3-6)=0
Domain of the equation: 3(3x+3-6)!=0We add all the numbers together, and all the variables
x∈R
x-4(x+3)-(1/3(3x-3)=0
We multiply parentheses
x-4x-(1/3(3x-3)-12=0
We multiply all the terms by the denominator
x*3(3x-3)-4x*3(3x-3)-12-12-(1=0
We add all the numbers together, and all the variables
x*3(3x-3)-4x*3(3x-3)=0
Wy multiply elements
3x^2(3-12x^2(3=0
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