x-4(x+3)=8-(8x+10)

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Solution for x-4(x+3)=8-(8x+10) equation: 



x-4(x+3)=8-(8x+10)

We move all terms to the left:

x-4(x+3)-(8-(8x+10))=0

We multiply parentheses

x-4x-(8-(8x+10))-12=0



We calculate terms in parentheses: -(8-(8x+10)), so:

8-(8x+10)

determiningTheFunctionDomain
-(8x+10)+8

We get rid of parentheses

-8x-10+8

We add all the numbers together, and all the variables

-8x-2

Back to the equation:

-(-8x-2)



We add all the numbers together, and all the variables

-3x-(-8x-2)-12=0

We get rid of parentheses

-3x+8x+2-12=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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