If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x-(4/2) = x+1/9 // - x+1/9
x-x-(4/2)-(1/9) = 0
x-x-1/9-2 = 0
-19/9 = 0
x belongs to the empty set
x belongs to the empty set
| x/8=9/0.6 | | 10x^2-35x-20=0 | | 5x-10=2x-16 | | 1/3x*2=-6 | | 4x+14=26 | | 3/8=x/60 | | -x+4=-2x | | X+40+45+90=360 | | 5w/6+2=7w/10 | | Z+1=.5+4 | | 6y-6= | | 3x^2-12x+0=0 | | 5/2=x-8/x-2 | | 37.4=2h(4.3+6.7) | | (4x^2+5x)(12x^2-5x-2)=0 | | 6x^2-15-x=0 | | r^2+r+72=0 | | x^2+19x+100=0 | | 28=(4w-1)/5+(9w+3)/4 | | 12-3x=-9 | | 5y+2x=3 | | 7/10=20/x | | 3(x-7)-3(2x-4)=4(x+3) | | 2p-15+9p=6p-36-19 | | k+5/7=5/3 | | -10x-80=40 | | 10x^2=7x+12 | | 4t^2+4t-15=0 | | 100+15=75+17 | | 9x^2+27x-90= | | 10x-12+3x=0 | | 28=4w-1/5+9w+3/4 |