x-4/3x+1=x+4/x

Solution for x-4/3x+1=x+4/x equation:

x-4/3x+1=x+4/x

We move all terms to the left:

x-4/3x+1-(x+4/x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-4/3x-(+x+4/x)+1=0

We get rid of parentheses

x-4/3x-x-4/x+1=0

We calculate fractions


x-x+(-4x)/3x^2+(-12x)/3x^2+1=0

We add all the numbers together, and all the variables

(-4x)/3x^2+(-12x)/3x^2+1=0

We multiply all the terms by the denominator


(-4x)+(-12x)+1*3x^2=0

Wy multiply elements

3x^2+(-4x)+(-12x)=0

We get rid of parentheses

3x^2-4x-12x=0

We add all the numbers together, and all the variables

3x^2-16x=0

a = 3; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·3·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*3}=\frac{32}{6}
=5+1/3
$