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x-4/3x-12=3
We move all terms to the left:
x-4/3x-12-(3)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x-4/3x-15=0
We multiply all the terms by the denominator
x*3x-15*3x-4=0
Wy multiply elements
3x^2-45x-4=0
a = 3; b = -45; c = -4;
Δ = b2-4ac
Δ = -452-4·3·(-4)
Δ = 2073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2073}}{2*3}=\frac{45-\sqrt{2073}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2073}}{2*3}=\frac{45+\sqrt{2073}}{6} $
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