x-4/x+5

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Solution for x-4/x+5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(4/x)+5 = 0

x-4*x^-1+5 = 0

1*x^1-4*x^-1+5*x^0 = 0

(1*x^2+5*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+5*x^1-4*x^0) = 0

x^1

x^2+5*x-4 = 0

x^2+5*x-4 = 0

DELTA = 5^2-(-4*1*4)

DELTA = 41

DELTA > 0

x = (41^(1/2)-5)/(1*2) or x = (-41^(1/2)-5)/(1*2)

x = (41^(1/2)-5)/2 or x = (-(41^(1/2)+5))/2

x in { (-(41^(1/2)+5))/2, (41^(1/2)-5)/2} 

x in { (-(41^(1/2)+5))/2, (41^(1/2)-5)/2 }

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