x-40-5(x+35)=25-9(x-5)

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Solution for x-40-5(x+35)=25-9(x-5) equation: 



x-40-5(x+35)=25-9(x-5)

We move all terms to the left:

x-40-5(x+35)-(25-9(x-5))=0

We multiply parentheses

x-5x-(25-9(x-5))-175-40=0



We calculate terms in parentheses: -(25-9(x-5)), so:

25-9(x-5)

determiningTheFunctionDomain
-9(x-5)+25

We multiply parentheses

-9x+45+25

We add all the numbers together, and all the variables

-9x+70

Back to the equation:

-(-9x+70)



We add all the numbers together, and all the variables

-4x-(-9x+70)-215=0

We get rid of parentheses

-4x+9x-70-215=0

We add all the numbers together, and all the variables

5x-285=0

We move all terms containing x to the left, all other terms to the right

5x=285

x=285/5

x=57

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