x-40-5(x+35)=25-9(x-5)

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Solution for x-40-5(x+35)=25-9(x-5) equation:



x-40-5(x+35)=25-9(x-5)
We move all terms to the left:
x-40-5(x+35)-(25-9(x-5))=0
We multiply parentheses
x-5x-(25-9(x-5))-175-40=0
We calculate terms in parentheses: -(25-9(x-5)), so:
25-9(x-5)
determiningTheFunctionDomain -9(x-5)+25
We multiply parentheses
-9x+45+25
We add all the numbers together, and all the variables
-9x+70
Back to the equation:
-(-9x+70)
We add all the numbers together, and all the variables
-4x-(-9x+70)-215=0
We get rid of parentheses
-4x+9x-70-215=0
We add all the numbers together, and all the variables
5x-285=0
We move all terms containing x to the left, all other terms to the right
5x=285
x=285/5
x=57

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