x-40=8(2x+3)-19

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Solution for x-40=8(2x+3)-19 equation: 



x-40=8(2x+3)-19

We move all terms to the left:

x-40-(8(2x+3)-19)=0



We calculate terms in parentheses: -(8(2x+3)-19), so:

8(2x+3)-19

We multiply parentheses

16x+24-19

We add all the numbers together, and all the variables

16x+5

Back to the equation:

-(16x+5)



We get rid of parentheses

x-16x-5-40=0

We add all the numbers together, and all the variables

-15x-45=0

We move all terms containing x to the left, all other terms to the right

-15x=45

x=45/-15

x=-3

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