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x-45=3x(x+25)
We move all terms to the left:
x-45-(3x(x+25))=0
We calculate terms in parentheses: -(3x(x+25)), so:We get rid of parentheses
3x(x+25)
We multiply parentheses
3x^2+75x
Back to the equation:
-(3x^2+75x)
-3x^2+x-75x-45=0
We add all the numbers together, and all the variables
-3x^2-74x-45=0
a = -3; b = -74; c = -45;
Δ = b2-4ac
Δ = -742-4·(-3)·(-45)
Δ = 4936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4936}=\sqrt{4*1234}=\sqrt{4}*\sqrt{1234}=2\sqrt{1234}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-2\sqrt{1234}}{2*-3}=\frac{74-2\sqrt{1234}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+2\sqrt{1234}}{2*-3}=\frac{74+2\sqrt{1234}}{-6} $
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