x-4=2(x-8)/5

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Solution for x-4=2(x-8)/5 equation: 



x-4=2(x-8)/5

We move all terms to the left:

x-4-(2(x-8)/5)=0

We multiply all the terms by the denominator


x*5)-(2(x-8)-4*5)=0

We add all the numbers together, and all the variables

x*5)-(2(x-8)=0

Wy multiply elements

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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