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x-4=2x^2+2
We move all terms to the left:
x-4-(2x^2+2)=0
We get rid of parentheses
-2x^2+x-2-4=0
We add all the numbers together, and all the variables
-2x^2+x-6=0
a = -2; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·(-2)·(-6)
Δ = -47
Delta is less than zero, so there is no solution for the equation
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