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x-4=8/3x-24
We move all terms to the left:
x-4-(8/3x-24)=0
Domain of the equation: 3x-24)!=0We get rid of parentheses
x∈R
x-8/3x+24-4=0
We multiply all the terms by the denominator
x*3x+24*3x-4*3x-8=0
Wy multiply elements
3x^2+72x-12x-8=0
We add all the numbers together, and all the variables
3x^2+60x-8=0
a = 3; b = 60; c = -8;
Δ = b2-4ac
Δ = 602-4·3·(-8)
Δ = 3696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3696}=\sqrt{16*231}=\sqrt{16}*\sqrt{231}=4\sqrt{231}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{231}}{2*3}=\frac{-60-4\sqrt{231}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{231}}{2*3}=\frac{-60+4\sqrt{231}}{6} $
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