x-4y=2;y=3x+5

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Solution for x-4y=2;y=3x+5 system of equations: 


  • /| x-(4*y)-2 = 0| y-(3*x)-5 = 0
  • We try to solve the equation: x-(4*y)-2 = 0
  • x-4*y-2 = 0 // - x-2
  • -4*y = -(x-2) // : -4
  • y = (-(x-2))/(-4)
  • y = (2-x)/(-4)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (2-x)/(-4)-(3*x)-5 = 0| y = (2-x)/(-4)
  • (2-x)/(-4)-3*x-5 = 0
  • -11/4*x-5-1/2 = 0
  • -11/4*x-11/2 = 0
  • -11/4*x-11/2 = 0 // + 11/2
  • -11/4*x = 11/2 // : -11/4
  • x = 11/2/(-11/4)
  • x = -2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (2-x)/(-4): 
  • y = (2+2)/(-4)
  • y = 4/(-4)
  • y = -1
  • We get a system of equations:
  • /| y = -1| x = -2

 

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