x-5(2-3x)=4(2x-3)

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Solution for x-5(2-3x)=4(2x-3) equation: 



x-5(2-3x)=4(2x-3)

We move all terms to the left:

x-5(2-3x)-(4(2x-3))=0

We add all the numbers together, and all the variables

x-5(-3x+2)-(4(2x-3))=0

We multiply parentheses

x+15x-(4(2x-3))-10=0



We calculate terms in parentheses: -(4(2x-3)), so:

4(2x-3)

We multiply parentheses

8x-12

Back to the equation:

-(8x-12)



We add all the numbers together, and all the variables

16x-(8x-12)-10=0

We get rid of parentheses

16x-8x+12-10=0

We add all the numbers together, and all the variables

8x+2=0

We move all terms containing x to the left, all other terms to the right

8x=-2

x=-2/8

x=-1/4

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