x-5(x-2)=7-(3x+3)

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Solution for x-5(x-2)=7-(3x+3) equation: 



x-5(x-2)=7-(3x+3)

We move all terms to the left:

x-5(x-2)-(7-(3x+3))=0

We multiply parentheses

x-5x-(7-(3x+3))+10=0



We calculate terms in parentheses: -(7-(3x+3)), so:

7-(3x+3)

determiningTheFunctionDomain
-(3x+3)+7

We get rid of parentheses

-3x-3+7

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

-4x-(-3x+4)+10=0

We get rid of parentheses

-4x+3x-4+10=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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