x-5(y+2)+(3y-x)=0

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Solution for x-5(y+2)+(3y-x)=0 equation:


Simplifying
x + -5(y + 2) + (3y + -1x) = 0

Reorder the terms:
x + -5(2 + y) + (3y + -1x) = 0
x + (2 * -5 + y * -5) + (3y + -1x) = 0
x + (-10 + -5y) + (3y + -1x) = 0

Reorder the terms:
x + -10 + -5y + (-1x + 3y) = 0

Remove parenthesis around (-1x + 3y)
x + -10 + -5y + -1x + 3y = 0

Reorder the terms:
-10 + x + -1x + -5y + 3y = 0

Combine like terms: x + -1x = 0
-10 + 0 + -5y + 3y = 0
-10 + -5y + 3y = 0

Combine like terms: -5y + 3y = -2y
-10 + -2y = 0

Solving
-10 + -2y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -2y = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -2y = 0 + 10
-2y = 0 + 10

Combine like terms: 0 + 10 = 10
-2y = 10

Divide each side by '-2'.
y = -5

Simplifying
y = -5

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