x-5+2(3x+1)=-7(x+1)

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Solution for x-5+2(3x+1)=-7(x+1) equation: 



x-5+2(3x+1)=-7(x+1)

We move all terms to the left:

x-5+2(3x+1)-(-7(x+1))=0

We multiply parentheses

x+6x-(-7(x+1))+2-5=0



We calculate terms in parentheses: -(-7(x+1)), so:

-7(x+1)

We multiply parentheses

-7x-7

Back to the equation:

-(-7x-7)



We add all the numbers together, and all the variables

7x-(-7x-7)-3=0

We get rid of parentheses

7x+7x+7-3=0

We add all the numbers together, and all the variables

14x+4=0

We move all terms containing x to the left, all other terms to the right

14x=-4

x=-4/14

x=-2/7

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