x-5+2(x-4)=3(x+1)-5

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Solution for x-5+2(x-4)=3(x+1)-5 equation: 


Simplifying
x + -5 + 2(x + -4) = 3(x + 1) + -5

Reorder the terms:
x + -5 + 2(-4 + x) = 3(x + 1) + -5
x + -5 + (-4 * 2 + x * 2) = 3(x + 1) + -5
x + -5 + (-8 + 2x) = 3(x + 1) + -5

Reorder the terms:
-5 + -8 + x + 2x = 3(x + 1) + -5

Combine like terms: -5 + -8 = -13
-13 + x + 2x = 3(x + 1) + -5

Combine like terms: x + 2x = 3x
-13 + 3x = 3(x + 1) + -5

Reorder the terms:
-13 + 3x = 3(1 + x) + -5
-13 + 3x = (1 * 3 + x * 3) + -5
-13 + 3x = (3 + 3x) + -5

Reorder the terms:
-13 + 3x = 3 + -5 + 3x

Combine like terms: 3 + -5 = -2
-13 + 3x = -2 + 3x

Add '-3x' to each side of the equation.
-13 + 3x + -3x = -2 + 3x + -3x

Combine like terms: 3x + -3x = 0
-13 + 0 = -2 + 3x + -3x
-13 = -2 + 3x + -3x

Combine like terms: 3x + -3x = 0
-13 = -2 + 0
-13 = -2

Solving
-13 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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