x-5/(x+2)(x-4)

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Solution for x-5/(x+2)(x-4) equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

x-((5/(x+2))*(x-4)) = 0

x-5*(x+2)^-1*(x-4) = 0

(-5*(x-4))/(x+2)+x = 0

(-5*(x-4))/(x+2)+(x*(x+2))/(x+2) = 0

x*(x+2)-5*(x-4) = 0

x^2-3*x+20 = 0

x^2-3*x+20 = 0

x^2-3*x+20 = 0

DELTA = (-3)^2-(1*4*20)

DELTA = -71

DELTA < 0

1 = 0

1/(x+2) = 0

1/(x+2) = 0 // * x+2

1 = 0

x belongs to the empty set

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