If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x-(5/2)-1 = x-(11/3) // - x-(11/3)
x-x-(5/2)+11/3-1 = 0
x-x-5/2+11/3-1 = 0
1/6 = 0
x belongs to the empty set
x belongs to the empty set
| p-2=6p-4 | | v=.5(3.14)r(r)h | | x/2-x=-2 | | 5x/7-8=x | | 1x+8y=-3 | | (12k^2-12k)/18k^2 | | x-5/2-1=x-10/3 | | 12k^2-12k/18k^2 | | 8(0)+5y=-180 | | 6+(-5)*X= | | x-4/5-1=x-12/6 | | 8(5)+5y=-180 | | 8(-36)+5y=-180 | | 2x/5-x=x/15-8/3 | | (2x+(13x-3)/(x-4))/(2x+(x+3)/(x-4)) | | -4(-3)(-1)(-4)= | | 6-5*x=x+10 | | 8n/100 | | Z-12/3=4 | | 5x-5/2x^2+8x+8 | | 64+-32x=55+-35x | | 5(-4)(2)= | | 3y/10-4=y/5+2 | | 60-(2x-5)=11/4 | | 64-32x=55-32x | | 6a+3b+2c=360 | | -2(5n-7)+3n-(n+4)=26 | | y=16-4-20 | | tanx=-1.5 | | y=1+1-20 | | 1/3(2x-5)+3 | | y=25+5-20 |