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x-5/3x-18=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x*3x-18*3x-5=0
Wy multiply elements
3x^2-54x-5=0
a = 3; b = -54; c = -5;
Δ = b2-4ac
Δ = -542-4·3·(-5)
Δ = 2976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2976}=\sqrt{16*186}=\sqrt{16}*\sqrt{186}=4\sqrt{186}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-4\sqrt{186}}{2*3}=\frac{54-4\sqrt{186}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+4\sqrt{186}}{2*3}=\frac{54+4\sqrt{186}}{6} $
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