If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
x-(5/4)-2 = x-(5/3) // - x-(5/3)
x-x-(5/4)+5/3-2 = 0
x-x-5/4+5/3-2 = 0
-19/12 = 0
x belongs to the empty set
x belongs to the empty set
| (x^2/y)/(x/y^2) | | 29f=145 | | 27=p/17 | | 2(3-x)=4-5x | | (2n+21)+(4n+15)= | | z/28=14 | | 90=11x+9+2x | | 7-2n=n-7 | | X^2-6x+45= | | 8d+2d+5d+6=5d | | x^2-5x-13=23 | | 0.55=z/-3 | | z/16=-24 | | -3(5t-5)+6t=2t-2 | | K+3=1d | | 8x+4x-3x=24 | | -5+3x=3(x-1)-2 | | 15=c/12 | | 2.1r+.02q=3.16-.2r | | -205=v-634 | | 6/4y-12=6 | | 4x-3(6-2x)=3x+4 | | 8y=384 | | 7x-4=7x-9 | | Y=3-3/2x | | c-150=980 | | q^2-17q=-72 | | 5(3m-6)=10 | | 629=17t | | 20/30=×/6 | | 3x-7+7x+6=6x+7+4x-8 | | 18=n/29 |