x-5/7(x-5)=x+5/3(x+5)

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Solution for x-5/7(x-5)=x+5/3(x+5) equation: 



x-5/7(x-5)=x+5/3(x+5)

We move all terms to the left:

x-5/7(x-5)-(x+5/3(x+5))=0



Domain of the equation: 7(x-5)!=0

x∈R





Domain of the equation: 3(x+5))!=0

x∈R



We calculate fractions


x+(-15xx/(7(x-5)*3(x+5)))+(-(x+35xx)/(7(x-5)*3(x+5)))=0



We calculate terms in parentheses: +(-15xx/(7(x-5)*3(x+5))), so:

-15xx/(7(x-5)*3(x+5))

We multiply all the terms by the denominator


-15xx

Back to the equation:

+(-15xx)





We calculate terms in parentheses: +(-(x+35xx)/(7(x-5)*3(x+5))), so:

-(x+35xx)/(7(x-5)*3(x+5))

We add all the numbers together, and all the variables

-(+x+35xx)/(7(x-5)*3(x+5))

We multiply all the terms by the denominator


-(+x+35xx)

We get rid of parentheses

-x-35xx

We add all the numbers together, and all the variables

-1x-35xx

Back to the equation:

+(-1x-35xx)



We get rid of parentheses

x-15xx-1x-35xx=0

We add all the numbers together, and all the variables

-15xx-35xx=0

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