x-58=6(2x+3)-10

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Solution for x-58=6(2x+3)-10 equation:



x-58=6(2x+3)-10
We move all terms to the left:
x-58-(6(2x+3)-10)=0
We calculate terms in parentheses: -(6(2x+3)-10), so:
6(2x+3)-10
We multiply parentheses
12x+18-10
We add all the numbers together, and all the variables
12x+8
Back to the equation:
-(12x+8)
We get rid of parentheses
x-12x-8-58=0
We add all the numbers together, and all the variables
-11x-66=0
We move all terms containing x to the left, all other terms to the right
-11x=66
x=66/-11
x=-6

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