x-5=-6+3/2x

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Solution for x-5=-6+3/2x equation:



x-5=-6+3/2x
We move all terms to the left:
x-5-(-6+3/2x)=0
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
x-(3/2x-6)-5=0
We get rid of parentheses
x-3/2x+6-5=0
We multiply all the terms by the denominator
x*2x+6*2x-5*2x-3=0
Wy multiply elements
2x^2+12x-10x-3=0
We add all the numbers together, and all the variables
2x^2+2x-3=0
a = 2; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·2·(-3)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{7}}{2*2}=\frac{-2-2\sqrt{7}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{7}}{2*2}=\frac{-2+2\sqrt{7}}{4} $

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