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x-5=2(x+3)-x
We move all terms to the left:
x-5-(2(x+3)-x)=0
We calculate terms in parentheses: -(2(x+3)-x), so:We get rid of parentheses
2(x+3)-x
We add all the numbers together, and all the variables
-1x+2(x+3)
We multiply parentheses
-1x+2x+6
We add all the numbers together, and all the variables
x+6
Back to the equation:
-(x+6)
x-x-6-5=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation
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