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x-6/3x+8=x+5/x
We move all terms to the left:
x-6/3x+8-(x+5/x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-6/3x-(+x+5/x)+8=0
We get rid of parentheses
x-6/3x-x-5/x+8=0
We calculate fractions
x-x+(-6x)/3x^2+(-15x)/3x^2+8=0
We add all the numbers together, and all the variables
(-6x)/3x^2+(-15x)/3x^2+8=0
We multiply all the terms by the denominator
(-6x)+(-15x)+8*3x^2=0
Wy multiply elements
24x^2+(-6x)+(-15x)=0
We get rid of parentheses
24x^2-6x-15x=0
We add all the numbers together, and all the variables
24x^2-21x=0
a = 24; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·24·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*24}=\frac{42}{48} =7/8 $
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