x-7(3x-2)=7x-3(1+2x)

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Solution for x-7(3x-2)=7x-3(1+2x) equation: 



x-7(3x-2)=7x-3(1+2x)

We move all terms to the left:

x-7(3x-2)-(7x-3(1+2x))=0

We add all the numbers together, and all the variables

x-7(3x-2)-(7x-3(2x+1))=0

We multiply parentheses

x-21x-(7x-3(2x+1))+14=0



We calculate terms in parentheses: -(7x-3(2x+1)), so:

7x-3(2x+1)

We multiply parentheses

7x-6x-3

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We add all the numbers together, and all the variables

-20x-(x-3)+14=0

We get rid of parentheses

-20x-x+3+14=0

We add all the numbers together, and all the variables

-21x+17=0

We move all terms containing x to the left, all other terms to the right

-21x=-17

x=-17/-21

x=17/21

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