x-7/5x+1=x+4/x

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Solution for x-7/5x+1=x+4/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-((7/5)*x)+1 = x+4/x // - x+4/x

x-((7/5)*x)-x-(4/x)+1 = 0

x+(-7/5)*x-x-4*x^-1+1 = 0

1*x^0-7/5*x^1-4*x^-1 = 0

(1*x^1-7/5*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^1-7/5*x^2-4*x^0) = 0

x^1

(-7/5)*x^2+x-4 = 0

(-7/5)*x^2+x-4 = 0

DELTA = 1^2-(-4*4*(-7/5))

DELTA = -107/5

DELTA < 0

x in { } 

x belongs to the empty set

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