x-8(5+2x)=-5(2x-1)-20

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Solution for x-8(5+2x)=-5(2x-1)-20 equation: 



x-8(5+2x)=-5(2x-1)-20

We move all terms to the left:

x-8(5+2x)-(-5(2x-1)-20)=0

We add all the numbers together, and all the variables

x-8(2x+5)-(-5(2x-1)-20)=0

We multiply parentheses

x-16x-(-5(2x-1)-20)-40=0



We calculate terms in parentheses: -(-5(2x-1)-20), so:

-5(2x-1)-20

We multiply parentheses

-10x+5-20

We add all the numbers together, and all the variables

-10x-15

Back to the equation:

-(-10x-15)



We add all the numbers together, and all the variables

-15x-(-10x-15)-40=0

We get rid of parentheses

-15x+10x+15-40=0

We add all the numbers together, and all the variables

-5x-25=0

We move all terms containing x to the left, all other terms to the right

-5x=25

x=25/-5

x=-5

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