x-8=-3(2x-4)+3x

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Solution for x-8=-3(2x-4)+3x equation: 



x-8=-3(2x-4)+3x

We move all terms to the left:

x-8-(-3(2x-4)+3x)=0



We calculate terms in parentheses: -(-3(2x-4)+3x), so:

-3(2x-4)+3x

We add all the numbers together, and all the variables

3x-3(2x-4)

We multiply parentheses

3x-6x+12

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We get rid of parentheses

x+3x-12-8=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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