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x-9=2/3x
We move all terms to the left:
x-9-(2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+2/3x)-9=0
We get rid of parentheses
x-2/3x-9=0
We multiply all the terms by the denominator
x*3x-9*3x-2=0
Wy multiply elements
3x^2-27x-2=0
a = 3; b = -27; c = -2;
Δ = b2-4ac
Δ = -272-4·3·(-2)
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{753}}{2*3}=\frac{27-\sqrt{753}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{753}}{2*3}=\frac{27+\sqrt{753}}{6} $
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