x-x/4x-x/12-x/36=46

Solution for x-x/4x-x/12-x/36=46 equation:

x-x/4x-x/12-x/36=46

We move all terms to the left:

x-x/4x-x/12-x/36-(46)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


(-432x^2)/5184x+(-48x^2)/5184x+x+(-1296x)/5184x-46=0

We multiply all the terms by the denominator


(-432x^2)+(-48x^2)+x*5184x+(-1296x)-46*5184x=0

Wy multiply elements

(-432x^2)+(-48x^2)+5184x^2+(-1296x)-238464x=0

We get rid of parentheses

-432x^2-48x^2+5184x^2-1296x-238464x=0

We add all the numbers together, and all the variables

4704x^2-239760x=0

a = 4704; b = -239760; c = 0;
Δ = b2-4ac
Δ = -2397602-4·4704·0
Δ = 57484857600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57484857600}=239760$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-239760)-239760}{2*4704}=\frac{0}{9408}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-239760)+239760}{2*4704}=\frac{479520}{9408}
=50+95/98
$