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x.2(4x+5)-2=2x+44
We move all terms to the left:
x.2(4x+5)-2-(2x+44)=0
We multiply parentheses
4x^2+5x-(2x+44)-2=0
We get rid of parentheses
4x^2+5x-2x-44-2=0
We add all the numbers together, and all the variables
4x^2+3x-46=0
a = 4; b = 3; c = -46;
Δ = b2-4ac
Δ = 32-4·4·(-46)
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{745}}{2*4}=\frac{-3-\sqrt{745}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{745}}{2*4}=\frac{-3+\sqrt{745}}{8} $
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