x.4(3x-1)+7-x=2x+3+9x

Solution for x.4(3x-1)+7-x=2x+3+9x equation:

x.4(3x-1)+7-x=2x+3+9x

We move all terms to the left:

x.4(3x-1)+7-x-(2x+3+9x)=0

We add all the numbers together, and all the variables

x.4(3x-1)-x-(11x+3)+7=0

We add all the numbers together, and all the variables

-1x+x.4(3x-1)-(11x+3)+7=0

We multiply parentheses

3x^2-1x-1x-(11x+3)+7=0

We get rid of parentheses

3x^2-1x-1x-11x-3+7=0

We add all the numbers together, and all the variables

3x^2-13x+4=0

a = 3; b = -13; c = +4;
Δ = b2-4ac
Δ = -132-4·3·4
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-11}{2*3}=\frac{2}{6}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+11}{2*3}=\frac{24}{6}
=4
$