x.6(x+2)+2x-4=8(x-2)

Solution for x.6(x+2)+2x-4=8(x-2) equation:

x.6(x+2)+2x-4=8(x-2)

We move all terms to the left:

x.6(x+2)+2x-4-(8(x-2))=0

We add all the numbers together, and all the variables

2x+x.6(x+2)-(8(x-2))-4=0

We multiply parentheses

x^2+2x+2x-(8(x-2))-4=0


We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)


We add all the numbers together, and all the variables

x^2+4x-(8x-16)-4=0

We get rid of parentheses

x^2+4x-8x+16-4=0

We add all the numbers together, and all the variables

x^2-4x+12=0

a = 1; b = -4; c = +12;
Δ = b2-4ac
Δ = -42-4·1·12
Δ = -32
Delta is less than zero, so there is no solution for the equation