x/(2x+1)(x-4)+13=2X2-10x

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Solution for x/(2x+1)(x-4)+13=2X2-10x equation: 



x/(2x+1)(x-4)+13=2x^2-10x

We move all terms to the left:

x/(2x+1)(x-4)+13-(2x^2-10x)=0



Domain of the equation: (2x+1)(x-4)!=0

We move all terms containing x to the left, all other terms to the right

2x+1)(x!=4

x∈R



We get rid of parentheses

-2x^2+x/(2x+1)(x-4)+10x+13=0

We multiply parentheses ..

-2x^2+x/(+2x^2-8x+x-4)+10x+13=0

We multiply all the terms by the denominator


-2x^2*(+2x^2-8x+x-4)+10x*(+2x^2-8x+x-4)+13*(+2x^2-8x+x-4)+x=0

We multiply parentheses

-2x^2*(+2x^2-8x+x-4)+20x^3-80x^2+10x^2+26x^2-40x-104x+13x+x-52=0

We do not support expression: x^3

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