x/(2x-1)+2/(x+2)=1

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Solution for x/(2x-1)+2/(x+2)=1 equation: 



x/(2x-1)+2/(x+2)=1

We move all terms to the left:

x/(2x-1)+2/(x+2)-(1)=0



Domain of the equation: (2x-1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=1

x!=1/2

x!=1/2

x∈R





Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We calculate fractions


(x^2+2x)/((2x-1)*(x+2))+(4x-2)/((2x-1)*(x+2))-1=0



We calculate terms in parentheses: +(x^2+2x)/((2x-1)*(x+2)), so:

x^2+2x)/((2x-1)*(x+2)

We multiply all the terms by the denominator


x^2*((2x-1)*(x+2)+2x)

Back to the equation:

+(x^2*((2x-1)*(x+2)+2x))





We calculate terms in parentheses: +(4x-2)/((2x-1)*(x+2)), so:

4x-2)/((2x-1)*(x+2)

We multiply all the terms by the denominator


4x*((2x-1)*(x+2)-2)

Back to the equation:

+(4x*((2x-1)*(x+2)-2))





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





We calculate terms in parentheses: +(x^2*((2x-1)*(x+2)+2x)), so:

x^2*((2x-1)*(x+2)+2x)





We calculate terms in parentheses: +(4x*((2x-1)*(x+2)-2)), so:

4x*((2x-1)*(x+2)-2)





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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