x/(x+1)-4/(x-2)=2

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Solution for x/(x+1)-4/(x-2)=2 equation: 


D( x )

x-2 = 0

x+1 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:2) U (2:+oo)

x/(x+1)-(4/(x-2)) = 2 // - 2

x/(x+1)-(4/(x-2))-2 = 0

x/(x+1)-4*(x-2)^-1-2 = 0

x/(x+1)-4/(x-2)-2 = 0

(x*(x-2))/((x+1)*(x-2))+(-4*(x+1))/((x+1)*(x-2))+(-2*(x+1)*(x-2))/((x+1)*(x-2)) = 0

x*(x-2)-4*(x+1)-2*(x+1)*(x-2) = 0

x^2-2*x^2-6*x+2*x-4+4 = 0

-x^2-4*x = 0

-x^2-4*x = 0

-x*(x+4) = 0

x+4 = 0 // - 4

x = -4

-x*(x+4) = 0

(-x*(x+4))/((x+1)*(x-2)) = 0

(-x*(x+4))/((x+1)*(x-2)) = 0 // * (x+1)*(x-2)

-x*(x+4) = 0

( -x )

-1*x = 0 // : -1

x = 0

( x+4 )

x+4 = 0 // - 4

x = -4

x in { 0, -4 }

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