x/(x-7)+3=7/(x-7)

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Solution for x/(x-7)+3=7/(x-7) equation: 


D( x )

x-7 = 0

x-7 = 0

x-7 = 0

x-7 = 0 // + 7

x = 7

x in (-oo:7) U (7:+oo)

x/(x-7)+3 = 7/(x-7) // - 7/(x-7)

x/(x-7)-(7/(x-7))+3 = 0

x/(x-7)-7*(x-7)^-1+3 = 0

x/(x-7)-7/(x-7)+3 = 0

x/(x-7)-7/(x-7)+(3*(x-7))/(x-7) = 0

3*(x-7)+x-7 = 0

x+3*x-21-7 = 0

4*x-28 = 0

(4*x-28)/(x-7) = 0

(4*x-28)/(x-7) = 0 // * x-7

4*x-28 = 0

4*x-28 = 0 // + 28

4*x = 28 // : 4

x = 28/4

x = 7

x in { 7} 

x belongs to the empty set

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