x/16=2(3x+1)/9

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Solution for x/16=2(3x+1)/9 equation: 



x/16=2(3x+1)/9

We move all terms to the left:

x/16-(2(3x+1)/9)=0

We calculate fractions


9x^2/()+(-(2(3x+1)*16)/()=0



We calculate terms in parentheses: +(-(2(3x+1)*16)/(), so:

-(2(3x+1)*16)/(

We multiply all the terms by the denominator


-(2(3x+1)*16)



We calculate terms in parentheses: -(2(3x+1)*16), so:

2(3x+1)*16

We multiply parentheses

96x+32

Back to the equation:

-(96x+32)



We get rid of parentheses

-96x-32

Back to the equation:

+(-96x-32)



We get rid of parentheses

9x^2/()-96x-32=0

We multiply all the terms by the denominator


9x^2-96x*()-32*()=0

We add all the numbers together, and all the variables

9x^2-96x*()=0

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