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x/16=2(3x+1)/9
We move all terms to the left:
x/16-(2(3x+1)/9)=0
We calculate fractions
9x^2/()+(-(2(3x+1)*16)/()=0
We calculate terms in parentheses: +(-(2(3x+1)*16)/(), so:We get rid of parentheses
-(2(3x+1)*16)/(
We multiply all the terms by the denominator
-(2(3x+1)*16)
We calculate terms in parentheses: -(2(3x+1)*16), so:We get rid of parentheses
2(3x+1)*16
We multiply parentheses
96x+32
Back to the equation:
-(96x+32)
-96x-32
Back to the equation:
+(-96x-32)
9x^2/()-96x-32=0
We multiply all the terms by the denominator
9x^2-96x*()-32*()=0
We add all the numbers together, and all the variables
9x^2-96x*()=0
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