x/18=2(3x+1)/9

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Solution for x/18=2(3x+1)/9 equation: 



x/18=2(3x+1)/9

We move all terms to the left:

x/18-(2(3x+1)/9)=0

We calculate fractions


9x^2/()+(-(2(3x+1)*18)/()=0



We calculate terms in parentheses: +(-(2(3x+1)*18)/(), so:

-(2(3x+1)*18)/(

We multiply all the terms by the denominator


-(2(3x+1)*18)



We calculate terms in parentheses: -(2(3x+1)*18), so:

2(3x+1)*18

We multiply parentheses

108x+36

Back to the equation:

-(108x+36)



We get rid of parentheses

-108x-36

Back to the equation:

+(-108x-36)



We get rid of parentheses

9x^2/()-108x-36=0

We multiply all the terms by the denominator


9x^2-108x*()-36*()=0

We add all the numbers together, and all the variables

9x^2-108x*()=0

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