x/2(3x+4)-3(x-1)=x-1

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Solution for x/2(3x+4)-3(x-1)=x-1 equation: 



x/2(3x+4)-3(x-1)=x-1

We move all terms to the left:

x/2(3x+4)-3(x-1)-(x-1)=0



Domain of the equation: 2(3x+4)!=0

x∈R



We multiply parentheses

x/2(3x+4)-3x-(x-1)+3=0

We get rid of parentheses

x/2(3x+4)-3x-x+1+3=0

We multiply all the terms by the denominator


x-3x*2(3x+4)-x*2(3x+4)+1*2(3x+4)+3*2(3x+4)=0

Wy multiply elements

-6x^2(3-2x^2(3+2x(3+6x(3+x=0

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