x/2(x-3)-2x/x+4=x/4(x-3)

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Solution for x/2(x-3)-2x/x+4=x/4(x-3) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x/2)*(x-3)-((2*x)/x)+4 = (x/4)*(x-3) // - (x/4)*(x-3)

(x/2)*(x-3)-((x/4)*(x-3))-((2*x)/x)+4 = 0

(x/2)*(x-3)-((x/4)*(x-3))-2+4 = 0

1/2*x*(x-3)-1*1/4*x*(x-3)-2+4 = 0

1/2*x*(x-3)-1*1/4*x*(x-3)-2+4 = 0

1/4*x^2-3/4*x-2+4 = 0

1/4*x^2-3/4*x+2 = 0

1/4*x^2-3/4*x+2 = 0

1/4*x^2-3/4*x+2 = 0

DELTA = (-3/4)^2-(1/4*2*4)

DELTA = -23/16

DELTA < 0

1 = 0

1 = 0

x belongs to the empty set

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