x/2-1/2(12-x)=7x+3(8-x)-8

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Solution for x/2-1/2(12-x)=7x+3(8-x)-8 equation: 



x/2-1/2(12-x)=7x+3(8-x)-8

We move all terms to the left:

x/2-1/2(12-x)-(7x+3(8-x)-8)=0



Domain of the equation: 2(12-x)!=0

x∈R



We add all the numbers together, and all the variables

x/2-1/2(-1x+12)-(7x+3(-1x+8)-8)=0

We calculate fractions


-(7x+3(-1x+8)-8)=0



We calculate terms in parentheses: -(7x+3(-1x+8)-8), so:

7x+3(-1x+8)-8

We multiply parentheses

7x-3x+24-8

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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